Spark004--总结前面的基本操作

实现排序功能

（1）按照价格排序

第一种

package com.ruozedata.spark.spark02

import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._

object SortApp01 {

  def main(args: Array[String]): Unit = {


    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)

    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"))
        products.map(x => {
          val splits = x.split(" ")
          val name = splits(0)
          val price = splits(1).toDouble
          val amount = splits(2).toInt

          (name, price, amount)
        }).sortBy(-_._2).printInfo()


      sc.stop()
    }

}
输出的结果：
(iphone11,7000.0,1000)
(皮鞭,20.0,10)
(蜡烛,20.0,100)
(扑克牌,5.0,2000)
-------------------------

这里一定要注意：
你运行出来的结果可能顺序不对，sortBy是全局排序的所以你测试的时候可以设置分区数为 1

上面的结果当然也可以按多个排：
价格相同，再按照库存的数量排序

package com.ruozedata.spark.spark02
import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._

object SortApp01 {

  def main(args: Array[String]): Unit = {

    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)

    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"),1)
        products.map(x => {
          val splits = x.split(" ")
          val name = splits(0)
          val price = splits(1).toDouble
          val amount = splits(2).toInt

          (name, price, amount)
        }).sortBy(x=>(-x._2,-x._3)).printInfo()
      sc.stop()
    }

}

结果：
(iphone11,7000.0,1000)
(蜡烛,20.0,100)
(皮鞭,20.0,10)
(扑克牌,5.0,2000)
-------------------------

上面那种是使用Tuple的方式，生产上还是要封装一个类来实现的

第二种

package com.ruozedata.spark.spark02

import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._

object SortApp02 {

  def main(args: Array[String]): Unit = {


    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)

    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"),1)
        products.map(x => {
          val splits = x.split(" ")
          val name = splits(0)
          val price = splits(1).toDouble
          val amount = splits(2).toInt

          new Products(name,price,amount)
        }).sortBy(x=>x).printInfo()


      sc.stop()
    }

}

直接报错：
Error:(21, 18) No implicit Ordering defined for com.ruozedata.spark.spark02.Products.
}).sortBy(x=>x).printInfo()
Error:(21, 18) not enough arguments for method sortBy: (implicit ord: Ordering[com.ruozedata.spark.spark02.Products], implicit ctag: scala.reflect.ClassTag[com.ruozedata.spark.spark02.Products])org.apache.spark.rdd.RDD[com.ruozedata.spark.spark02.Products].
Unspecified value parameters ord, ctag.
}).sortBy(x=>x).printInfo()

按上面那么写有什么问题？

 /**
   * Return this RDD sorted by the given key function.
   */
  def sortBy[K](
      f: (T) => K,
      ascending: Boolean = true,
      numPartitions: Int = this.partitions.length)
      (implicit ord: Ordering[K], ctag: ClassTag[K]): RDD[T] = withScope {
    this.keyBy[K](f)
        .sortByKey(ascending, numPartitions)
        .values
  }

注意：
1.有一个隐式转换的 需要一个Ordering 这个东西 ，而我们传进去的是x ==》 product 
它根本找不到任何排序规则

因为：
Error:(21, 18) not enough arguments for method sortBy: (implicit ord: Ordering[com.ruozedata.spark.spark02.Products], implicit ctag: scala.reflect.ClassTag[com.ruozedata.spark.spark02.Products])org.apache.spark.rdd.RDD[com.ruozedata.spark.spark02.Products].
所以：
1.not enough arguments
2.(implicit ord: Ordering[com.ruozedata.spark.spark02.Products] 一个Products类型

package com.ruozedata.spark.spark02

class Products(val name:String , val price:Double,val amount:Int) 
      extends  Ordered[Products]{
  override def compare(that: Products): Int = {
    
    this.amount - that.amount
  }
}

修改之后再看：
在这里插入图片描述
又报错了：
Serialization stack:
- object not serializable (class: com.ruozedata.spark.spark02.Products, value: com.ruozedata.spark.spark02.Products@237c4154)

class Products(val name:String , val price:Double,val amount:Int)
      extends  Ordered[Products] with Serializable{
  override def compare(that: Products): Int = {

    this.amount - that.amount
  }
}

修改之后：
在这里插入图片描述
没问题了那么我想看输出结果该怎么办呢？
toString 就可以了

class Products(val name:String , val price:Double,val amount:Int)
      extends  Ordered[Products] with Serializable{
  override def compare(that: Products): Int = {

    this.amount - that.amount
  }

  override def toString: String = name + "\t" + price + "\t" +amount
}

package com.ruozedata.spark.spark02

import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._

object SortApp02 {

  def main(args: Array[String]): Unit = {


    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)

    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"),1)
        products.map(x => {
          val splits = x.split(" ")
          val name = splits(0)
          val price = splits(1).toDouble
          val amount = splits(2).toInt

          new Products(name,price,amount)
        }).sortBy(x=>x).printInfo()


      sc.stop()
    }

}


结果：
皮鞭	20.0	10
蜡烛	20.0	100
iphone11	7000.0	1000
扑克牌	5.0	2000
-------------------------

工作当中别这么用毕竟自己实现类还需要序列化挺麻烦的

第三种 case class
生产上用的比较多

package com.ruozedata.spark.spark02

case  class  Products02( name:String,  price:Double,  amount:Int)
      extends  Ordered[Products02] {
  override def compare(that: Products02): Int = {

    this.amount - that.amount
  }

}

package com.ruozedata.spark.spark02

import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._

object SortApp02 {

  def main(args: Array[String]): Unit = {


    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)

    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"),1)
        products.map(x => {
          val splits = x.split(" ")
          val name = splits(0)
          val price = splits(1).toDouble
          val amount = splits(2).toInt

//          new Products(name,price,amount)
          Products02(name,price,amount)

        }).sortBy(x=>x).printInfo()


      sc.stop()
    }

}

结果是：
Products02(皮鞭,20.0,10)
Products02(蜡烛,20.0,100)
Products02(iphone11,7000.0,1000)
Products02(扑克牌,5.0,2000)
-------------------------

那么 class 和case class 的区别是什么？看scala篇

*第四种使用隐式转换的方式 *

package com.ruozedata.spark.spark02

import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._

object SortApp03 {

  def main(args: Array[String]): Unit = {
    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)
    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"),1)
        products.map(x => {
          val splits = x.split(" ")
          val name = splits(0)
          val price = splits(1).toDouble
          val amount = splits(2).toInt
          new Products03(name,price,amount)
        }).sortBy(x=>x).printInfo()
      sc.stop()
    }
}
class Products03( name:String,  price:Double,  amount:Int)

不准对Products03 做任何修改完成排序功能该怎么办？
Product3默认是不能排序的 ====implicit==> 能排序的

package com.ruozedata.spark.spark02

import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._

object SortApp03 {

  def main(args: Array[String]): Unit = {


    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)

    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"),1)
        products.map(x => {
          val splits = x.split(" ")
          val name = splits(0)
          val price = splits(1).toDouble
          val amount = splits(2).toInt

          new Products03(name,price,amount)

        }).sortBy(x=>x).printInfo()

    /**
      * Product3默认是不能排序的 ====implicit==> 能排序的
      */

    implicit def product2Ordered(products: Products03):Ordered[Products03] = new Ordered[Products03]{
      override def compare(that: Products03): Int = {
        products.amount - that.amount
      }
    }


    sc.stop()
    }
}

class Products03( val  name:String, val  price:Double,  val amount:Int) extends Serializable {
  override def toString: String = name + "\t" + price + "\t" + amount
}

第五种花里胡哨
能看懂就行不需要掌握
实际上也是隐式转换隐式变量

思路就是：
(implicit ord: Ordering[com.ruozedata.spark.spark02.Products] 一个Products类型

既然你却这个就隐式转换给你

package com.ruozedata.spark.spark02

import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._
import org.apache.spark.rdd.RDD

object SortApp04 {

  def main(args: Array[String]): Unit = {


    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)

    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"),1)
    val product = products.map(x => {
      val splits = x.split(" ")
      val name = splits(0)
      val price = splits(1).toDouble
      val amount = splits(2).toInt

      (name, price, amount)
    })


    /**
      * Ordering on
      *
      * -x._2, -x._3  排序规则
      * (Double,Int) 定义的是规则的返回值的类型  就是参与排序的 类型
      * (String,Double,Int) 数据的类型
      */
    implicit val ord = Ordering[(Double,Int)].on[(String,Double,Int)](x=>(-x._2, -x._3))
    product.sortBy(x=>x).printInfo()


      sc.stop()
    }

}



结果是：
(iphone11,7000.0,1000)
(蜡烛,20.0,100)
(皮鞭,20.0,10)
(扑克牌,5.0,2000)
-------------------------

package com.ruozedata.spark.spark02

import com.ruozedata.spark.homework.utils.ContextUtils
import com.ruozedata.spark.homework.utils.ImplicitAspect._
import org.apache.spark.rdd.RDD

object SortApp04 {

  def main(args: Array[String]): Unit = {


    val sc = ContextUtils.getSparkContext(this.getClass.getSimpleName)

    val products = sc.parallelize(List("皮鞭 20 10","蜡烛 20 100","扑克牌 5 2000","iphone11 7000 1000"),1)
    val product = products.map(x => {
      val splits = x.split(" ")
      val name = splits(0)
      val price = splits(1).toDouble
      val amount = splits(2).toInt

      Products02(name, price, amount)
    })


    /**
      * Ordering on
      *
      * -x._2, -x._3  排序规则
      * (Double,Int) 定义的是规则的返回值的类型  就是参与排序的 类型
      * (String,Double,Int) 数据的类型
      */
    implicit val ord = Ordering[(Double,Int)].on[Products02](x=>(-x.price, -x.amount))
    product.sortBy(x=>x).printInfo()


      sc.stop()
    }

}

总结：
后面两种都是隐式转换：
一个是增强类
一个是隐式参数 

隐式转换没什么 听着挺吓人的